b^2+4b+7b+28=

Solution for b^2+4b+7b+28= equation:

Simplifying
b2 + 4b + 7b + 28 = 0

Reorder the terms:
28 + 4b + 7b + b2 = 0

Combine like terms: 4b + 7b = 11b
28 + 11b + b2 = 0

Solving
28 + 11b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(7 + b)(4 + b) = 0

Subproblem 1
Set the factor '(7 + b)' equal to zero and attempt to solve:

Simplifying
7 + b = 0

Solving
7 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + b = 0 + -7

Combine like terms: 7 + -7 = 0
0 + b = 0 + -7
b = 0 + -7

Combine like terms: 0 + -7 = -7
b = -7

Simplifying
b = -7
Subproblem 2
Set the factor '(4 + b)' equal to zero and attempt to solve:

Simplifying
4 + b = 0

Solving
4 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + b = 0 + -4

Combine like terms: 4 + -4 = 0
0 + b = 0 + -4
b = 0 + -4

Combine like terms: 0 + -4 = -4
b = -4

Simplifying
b = -4
Solution
b = {-7, -4}